42\. 接雨水

# 42. 接雨水 (opens new window)

# Description

Difficulty: 困难

Related Topics: (opens new window), 数组 (opens new window), 双指针 (opens new window), 动态规划 (opens new window), 单调栈 (opens new window)

给定 n 个非负整数表示每个宽度为 1 的柱子的高度图,计算按此排列的柱子,下雨之后能接多少雨水。

示例 1:

输入:height = [0,1,0,2,1,0,1,3,2,1,2,1]
输出:6
解释:上面是由数组 [0,1,0,2,1,0,1,3,2,1,2,1] 表示的高度图,在这种情况下,可以接 6 个单位的雨水(蓝色部分表示雨水)。 
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示例 2:

输入:height = [4,2,0,3,2,5]
输出:9
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提示:

  • n == height.length
  • 1 <= n <= 2 * 104
  • 0 <= height[i] <= 105

# Solution

Language: JavaScript

/**
 * @param {number[]} height
 * @return {number}
 */
var trap = function(height) {
 const n = height.length
 const left = new Array(n).fill(0)
 const right = new Array(n).fill(0)
 let ans = 0
 for (let i = 1; i < n; i++) {
  left[i] = Math.max(left[i-1], height[i-1])
 }
 for (let i = n - 2; i >= 0; i--) {
  right[i] = Math.max(right[i + 1], height[i + 1])

  let short = Math.min(left[i], right[i]);
  if (short > height[i]) {
   ans += short - height[i]
  }
 }
 return ans
};
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上次更新: 2022/7/28 下午9:01:35