异步串行-异步并行
# 异步串行-异步并行
// 字节面试题,实现一个异步加法
function asyncAdd(a, b, callback) {
setTimeout(function () {
callback(null, a + b);
}, 500);
}
// 解决方案
// 1. promisify
const promiseAdd = (a, b) => new Promise((resolve, reject) => {
asyncAdd(a, b, (err, res) => {
if (err) {
reject(err)
} else {
resolve(res)
}
})
})
// 2. 串行处理
async function serialSum(...args) {
return args.reduce((task, now) => task.then(res => promiseAdd(res, now)), Promise.resolve(0))
}
// 3. 并行处理
async function parallelSum(...args) {
if (args.length === 1) return args[0]
const tasks = []
for (let i = 0; i < args.length; i += 2) {
tasks.push(promiseAdd(args[i], args[i + 1] || 0))
}
const results = await Promise.all(tasks)
return parallelSum(...results)
}
// 测试
(async () => {
console.log('Running...');
const res1 = await serialSum(1, 2, 3, 4, 5, 8, 9, 10, 11, 12)
console.log(res1)
const res2 = await parallelSum(1, 2, 3, 4, 5, 8, 9, 10, 11, 12)
console.log(res2)
console.log('Done');
})()
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44