54\. 螺旋矩阵

# 54. 螺旋矩阵 (opens new window)

# Description

Difficulty: 中等

Related Topics: 数组 (opens new window), 矩阵 (opens new window), 模拟 (opens new window)

给你一个 mn 列的矩阵 matrix ,请按照 顺时针螺旋顺序 ,返回矩阵中的所有元素。

示例 1:

输入:matrix = [[1,2,3],[4,5,6],[7,8,9]]
输出:[1,2,3,6,9,8,7,4,5]
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2

示例 2:

输入:matrix = [[1,2,3,4],[5,6,7,8],[9,10,11,12]]
输出:[1,2,3,4,8,12,11,10,9,5,6,7]
1
2

提示:

  • m == matrix.length
  • n == matrix[i].length
  • 1 <= m, n <= 10
  • -100 <= matrix[i][j] <= 100

# Solution

Language: JavaScript

/**
 * @param {number[][]} matrix
 * @return {number[]}
 */
var spiralOrder = function(matrix) {
    let n = []
    while (matrix.length) {
        n = _.concat(n, matrix.shift())
        matrix = _.reverse(_.zip(...matrix))
    }
    return n
};
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上次更新: 2022/8/31 上午3:18:49